x^2+5/3x+25/36=16/36

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Solution for x^2+5/3x+25/36=16/36 equation: 


x in (-oo:+oo)

x^2+(5/3)*x+25/36 = 16/36 // - 16/36

x^2+(5/3)*x+25/36-(16/36) = 0

x^2+(5/3)*x+25/36-4/9 = 0

x^2+5/3*x+1/4 = 0

DELTA = (5/3)^2-(1/4*1*4)

DELTA = 16/9

DELTA > 0

x = ((16/9)^(1/2)-5/3)/(1*2) or x = (-(16/9)^(1/2)-5/3)/(1*2)

x = -1/6 or x = -3/2

x in { -3/2, -1/6 }

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